WebNov 19, 2014 · 1. There is a 6 step process that will lead you to the answer but in many cases the key is to figure out which attribute or set of attributes have only out going … Web(1) To determine if the two sets F and G are equivalent or not, we need to check if each functional dependency in F can be derived from G and vice versa. Starting with F: A → B …
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WebConsider a relation R (A,B,C,D,E,F,G,H) with the following functional dependencies: A → BCD AD → E EFG → H F → GH (a) Based on these functional dependencies, there is one minimal key for R. What is it? (b) One of the four functional dependencies can be removed without altering the key. Which one? 5. WebGiven the relation schema R = (A, B, C, D, E, F, G, H) and the following set of functional dependencies: F = { A → B ABCD → E EF → G EF → H ACDF → EG } a) (4 marks) Compute the canonical cover for F. (Note: If this question looks familiar to you, you may be experiencing a case of déjà vu) Show your steps clearlyto get full marks!
WebAnswer to Solved (a) [10 points] Consider the relation schema \( R(A, This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. WebNCERT Solutions for Class 10 Science. NCERT Solutions for Class 10 Science Chapter 1; NCERT Solutions for Class 10 Science Chapter 2; NCERT Solutions for Class 10 Science Chapter 3
WebSep 22, 2024 · Consider the schema R = (A, B, C, D, E, G) and the set F of functional dependencies: AB → CD. B → D. DE → B. DEG → AB. AC → DE. R is not in BCNF for … WebConsider the schema R = (A, B, C, D, E, G) and the set F of functional dependencies: AB → CD B → D DE → B DEG → AB AC → DE R is not in BCNF for many reasons, one of …
Web(b) [12 points] Find a minimal cover for the relation schema R (A, B,C, D, E, F, G) with the set F = AB → C, C → A, BC → D, ACD → B, D → EG, BE → C, CG → BD, CE → G of (a) [10 points] Find a minimal cover for the relation schema R (A, B,C, D, E, F, G) with the set F = {A → DE, BCE → EG, E → C, DG → EF} of functional dependencies. Show each step.
Web1. [8 points) For the following set of functional dependencies on the relation schema R = (A, B, C, D, E, F, G): Compute the attribute closures: AB → CD a) {A, B}' = CEF GA b) {C}" GF CE → c) {G} II d) {C, E}* = e) What is the minimum candidate key for R? f) What are the prime attributes of R? g) What are the non-prime attributes of R? new minor fingWebNCERT Solutions for Class 10 Science. NCERT Solutions for Class 10 Science Chapter 1; NCERT Solutions for Class 10 Science Chapter 2; NCERT Solutions for Class 10 … intrinsic warframenew minnie mouse gamesWebApr 13, 2024 · Consider the relations r1( A, B, C), r2(C, D, E ), and r3( E , F), with primary keys A, C, and E, respectively. Assume that r1 has 1000 tuples, r2 has 1500 tuples, and r3 has 750 tuples. Estimate the size of r1 ⋈ r2 ⋈ r3, and give an efficient plan for computing the join. 2. Consider the following relational schema and SQL query. The schema … new minor forcing cohenWebJun 28, 2024 · Find the highest normal form of a relation R (A,B,C,D,E) with FD set {B->A, A->C, BC->D, AC->BE} Step 1. As we can see, (B) + = {B,A,C,D,E}, so B will be candidate key. B can be derived from AC using AC->B (Decomposing AC->BE to AC->B and AC->E). So AC will be super key but (C) + = {C} and (A) + = {A,C,B,E,D}. intrinsic wasting handWebD OWN SUN A New Profile Name E Existing Profile Name B Account Holder`s Name Currency GBP C Account Number CUA London Branch I Please fill in A, C, E below. Please fill in E below. Please fill in B, C, E below.] GCMS Plus : Application for UK Low Value Payment Information Maintenance Contact Person GBP Date of Sending a duplicate … new minomonsters of the multiverseWebNov 30, 2024 · Find the highest normal form of a relation R (A, B, C, D, E) with FD set as: { BC->D, AC->BE, B->E } Explanation: Step-1: As we can see, (AC)+ = {A, C, B, E, D} but none of its subset can determine all attribute of relation, So AC will be candidate key. new minor forcing bridge